ὑπεργηράω
ὑπεργηράω,
{
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{
"definition": "",
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"definition": "<i>grow exceedingly old,</i> Poll. 9.18, Men. Mon. 608: pf. ὑπεργεγήρακα A pollod. ap. D.L. 8.52, Aët. 16.26.",
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"ref": "Poll. 9.18,",
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"ref": "Men. Mon. 608:",
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"ref": "D.L. 8.52,",
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"ref": "Aët. 16.26.",
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],
"key": "u(perghra/w",
"type": "main"
}